Find the limit of $\frac{\sqrt{x+6}-4}{x-10}$ as $x$ approaches $10$

Step-by-step Solution

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Final answer to the problem

$\frac{1}{8}$
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Step-by-step Solution

How should I solve this problem?

  • Solve using L'Hôpital's rule
  • Solve without using l'Hôpital
  • Solve using limit properties
  • Solve using direct substitution
  • Solve the limit using factorization
  • Solve the limit using rationalization
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
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If we directly evaluate the limit $\lim_{x\to10}\left(\frac{\sqrt{x+6}-4}{x-10}\right)$ as $x$ tends to $10$, we can see that it gives us an indeterminate form

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$\frac{0}{0}$

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Learn how to solve limits by l'hôpital's rule problems step by step online. Find the limit of ((x+6)^(1/2)-4)/(x-10) as x approaches 10. If we directly evaluate the limit \lim_{x\to10}\left(\frac{\sqrt{x+6}-4}{x-10}\right) as x tends to 10, we can see that it gives us an indeterminate form. We can solve this limit by applying L'Hôpital's rule, which consists of calculating the derivative of both the numerator and the denominator separately. After deriving both the numerator and denominator, and simplifying, the limit results in. Multiplying the fraction by \left(x+6\right)^{-\frac{1}{2}}.

Final answer to the problem

$\frac{1}{8}$

Exact Numeric Answer

$0.125$

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Function Plot

Plotting: $\frac{\sqrt{x+6}-4}{x-10}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Limits by L'Hôpital's rule

In mathematics, and more specifically in calculus, L'Hôpital's rule uses derivatives to help evaluate limits involving indeterminate forms.

Used Formulas

See formulas (4)

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