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Solution

Videos

Calculus - How to use implicit differentiation with the square root for chain and product rule

https://www.youtube.com/watch?v=hQYG9yPrLco

Implicit Differentiation - Find The First &amp; Second Derivatives

https://www.youtube.com/watch?v=-XQDh6Z6DPI

Implicit Differentiation Explained - Product Rule, Quotient &amp; Chain Rule - Calculus

https://www.youtube.com/watch?v=LGY-DjFsALc

Implicit differentiation, product and chain rules at once

https://www.youtube.com/watch?v=BSrJi9uEJp0

Basic Differentiation Rules For Derivatives

https://www.youtube.com/watch?v=IvLpN1G1Ncg

how to take the derivative of arctan with product rule and chain

https://www.youtube.com/watch?v=8iyGt6kn9kI

Similar Problems Solved

$\frac{d}{dx}\left(xe^{2x}\right)$

$\frac{d}{dx}\left(x^3e^x\right)$

$\frac{d}{dx}\left(x^2\arccos\left(x\right)\right)$

$\frac{d}{dx}\left(x\arctan\left(x\right)\right)$

$\frac{d}{dx}\left(\mathrm{sech}\left(-4x\right)\left(1-\ln\left(\mathrm{sech}\left(-4x\right)\right)\right)\right)$

$\frac{d}{dx}\left(2x^3\tanh\left(\frac{1}{x^2}\right)\right)$

$\frac{d}{dx}\tan\left(x\right)$

Main Topic: Product Rule of differentiation

The product rule is a formula used to find the derivatives of products of two or more functions. It may be stated as $(f\cdot g)'=f'\cdot g+f\cdot g'$

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