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Find the derivative using logarithmic differentiation method $\frac{d}{dx}\left(y^3+4xy-e^{2x}\right)$

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 Solution

 Videos

Calculus - Find the derivative of natural logarithm using product property, d(ln(2x))/dx

https://www.youtube.com/watch?v=urYZhqwUTI0

Derivative of x^x^x, Logarithmic Differentiation of Exponential Functions, Calculus Youtube Video

https://www.youtube.com/watch?v=Vhltl9w6QNM

Implicit differentiation | Advanced derivatives | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=mSVrqKZDRF4

Worked example: Evaluating derivative with implicit differentiation | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=KyYC8XzKsHU

Implicit Differentiation - Find The First & Second Derivatives

https://www.youtube.com/watch?v=-XQDh6Z6DPI

Calculus - Using power rule with square root to take derivative on a logarithm, d(ln(sqrt(x+1)))/dx

https://www.youtube.com/watch?v=vbgVpjL8ucU

 Function Plot

Plotting: $\frac{y^{\prime}}{y}=\frac{1}{y^3+4xy-e^{2x}}\left(3y^{2}y^{\prime}+4\left(y+xy^{\prime}\right)-2e^{2x}\right)$

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0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Simplification of algebraic fractions

Simplification or reduction of algebraic fractions is the action of dividing the numerator and denominator of a fraction by a common factor in order to obtain another much simpler equivalent fraction. We can say that a fraction is reduced to its simplest when there is no common factor between the numerator and the denominator.

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