Simplify the expression $f\left(t\right)=\frac{2}{\sqrt{t}}+\frac{6}{\sqrt[3]{t^2}}$

Step-by-step Solution

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Final answer to the problem

$4\sqrt{t}+18\sqrt[3]{t}+C_0$
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Step-by-step Solution

How should I solve this problem?

  • Integrate by substitution
  • Solve by quadratic formula (general formula)
  • Find the derivative using the definition
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
  • Exact Differential Equation
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1

Find the integral

$\int\left(\frac{2}{\sqrt{t}}+\frac{6}{\sqrt[3]{t^2}}\right)dt$

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$\int\left(\frac{2}{\sqrt{t}}+\frac{6}{\sqrt[3]{t^2}}\right)dt$

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Unlock the first 3 steps of this solution

Learn how to solve problems step by step online. Simplify the expression f(t)=2/(t^(1/2))+6/(t^2^(1/3)). Find the integral. Simplify the expression. The integral \int\frac{2}{\sqrt{t}}dt results in: 4\sqrt{t}. The integral \int\frac{6}{\sqrt[3]{t^{2}}}dt results in: 18\sqrt[3]{t}.

Final answer to the problem

$4\sqrt{t}+18\sqrt[3]{t}+C_0$

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Function Plot

Plotting: $4\sqrt{t}+18\sqrt[3]{t}+C_0$

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Answer Assistant

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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