$\frac{2}{3}\left(4-2x\right)>\frac{1}{6}\left(4-8x\right)$

$\sqrt{\left(1+4x\right)^3}$

$\frac{x^2}{\left(2-x\right)^2}$

$\frac{4\sin\left(x\right)\cos\left(x\right)}{\cos^2\left(x\right)-\sin^2\left(x\right)}$

$\left(-4\right)^5x\left(-4\right)^1$

$\int\frac{5}{\sqrt{39+x^2}}dx$