$-2x^3+12x^2-6x-20$
$\left(-20\right)-\left(10-15\right)^2+\left[\left(-5\right)^2+\left(8-13\right)^2\right]$
$\left(5x^3+8y^5\right)^2$
$sec^2x-secx\cdot cos^2x=tan^2x$
$\sin x\cos x-\cos\theta=0$
$\frac{d}{dx}\sqrt{x\frac{1}{x+1}}$
$\lim_{x\to1}\:4lnx$
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