$1+\frac{2b}{3}+\frac{b^2}{9\left\{\right\}}$
$\lim\:_{x\to\:\infty}\left(\frac{\sqrt{3+2x^2}}{6+8x}\right)$
$\lim_{x\to1}\left(3x^3+2x^2-x+1\right)$
$16x-4x+k$
$\int\left(4x+12\right)^6dx$
$-3a^2b+3ab^2-b^3$
$\left(4a^2+5b^2\right)^2$
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