xy+3y cuando x= 2, y= 4xy+3y\:cuando\:x=\:2,\:\:y=\:4xy+3ycuandox=2,y=4
∫(x3+x−1)(x2+2)3dx\int\frac{\left(x^3+x-1\right)}{\left(x^2+2\right)^3}dx∫(x2+2)3(x3+x−1)dx
16⋅10−6\sqrt{16\cdot10^{-6}}16⋅10−6
lnx+ln(3x)=1lnx+ln\left(3x\right)=1lnx+ln(3x)=1
2ax+6ay−4az2ax+6ay-4az2ax+6ay−4az
y=1x2+3x+2y=1x^2+3x+2y=1x2+3x+2
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!