$\frac{2x^2+4x}{4x}$
$5=v+15$
$c\log\left(a\right)-y\log\left(b\right)$
$\left(5+2b+c\right)^2$
$\lim_{x\to\infty}\left(\frac{9x-6}{6x^2+4x+7}\right)$
$\left(a^3-9a^2b-b^3\right)-\left(25a^2-8ab^3-b^3\right)$
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