$3x^2-28x+25=8x^2-43x+43$
$0\:=\:3\:+\:v\:+\:\frac{1}{2}at^2$
$\tan\left(b\right)\left(\cot\left(b\right)+\tan\left(b\right)\right)=\sec\left(b\right)^2$
$\left(4x^2\right)-\left(2y^3\right)^3$
$14d^2-24d+9$
$\frac{3x^3-2x^2-2x-1}{x+1}$
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