$\int_2^3\left(-8e^{-2x+1}\right)dx$
$\lim x\to\:\infty\:\left(\frac{\left(1\:+\:x^2\right)e^x}{x}\right)$
$-13\:-8\:18$
$6\left(-5-9\right)-8\left[4-\left(2\cdot3-5\right)+1\right]$
$\int\frac{1}{x^3\left(x^3-1\right)^2}dx$
$tanxsinx-\sqrt{3}sinx=0$
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