$\lim_{x\to-1}\left(\frac{\left(8x^4+7x^3+6x+5\right)}{x+1}\right)$
$\:\frac{tan^2\theta\:}{sec^2\theta\:\:}$
$p+\sin\left(x\right)\csc\left(x\right)$
$\frac{1}{\tan^2\left(x\right)+1}=\cos\left(2x\right)$
$\left(6x^2-7\right)+\left(2x+3\right)$
$6\cos^2x+\cos2x=1$
$2x^2-6x-8x^3-12x^4$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!