Intermediate steps
Simplifying
$\int\left(x^2-5\right)^9\cdot2xdx$
$x^3+2x$
$6.3+4.21+0.129$
$\left(3y^2-1\right)\left(3y^2+1\right)$
$3\left(17\right)-19$
$\int_1^4\left(\frac{1}{x^2-3x}\right)dx$
$\left(5a+5b+5c\right)^2$
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