$\frac{6x^2-4^2+7x+3}{3x+1}$
$\frac{x^3}{\left(1+x^4\right)}$
$2x^2+1=9x-3$
$\left(x+8\right)\left(x+1\right)$
$-12+27-14-19+63-28$
$9x^2-64x+576$
$\tan\left(x\right)^2\left(\tan\left(x\right)^4+3\tan\left(x\right)^2+3\right)+1$
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