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Exercise

$\frac{\frac{\left(x^2-xy+y^2\right)}{x^3+y^3}}{\frac{1}{x+y}}$

Step-by-step Solution

1

We can simplify the quotient of fractions $\frac{\frac{x^2-xy+y^2}{x^3+y^3}}{\frac{1}{x+y}}$ by inverting the second fraction and multiply both fractions

$\frac{\left(x^2-xy+y^2\right)\left(x+y\right)}{1\left(x^3+y^3\right)}$

Final answer to the exercise

$\frac{\left(x^2-xy+y^2\right)\left(x+y\right)}{1\left(x^3+y^3\right)}$

Try other ways to solve this exercise

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  • Solve by quadratic formula (general formula)
  • Find the derivative using the definition
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  • Find the derivative
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Main Topic: Simplification of algebraic fractions

Simplification or reduction of algebraic fractions is the action of dividing the numerator and denominator of a fraction by a common factor in order to obtain another much simpler equivalent fraction. We can say that a fraction is reduced to its simplest when there is no common factor between the numerator and the denominator.

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