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f(x)=(2/sin(2x)-tan(x))/cos(x)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

2sin⁡(2x)−tan⁡(x)cos⁡(x)\frac{\frac{2}{\sin\left(2x\right)}-\tan\left(x\right)}{\cos\left(x\right)}

Step-by-step Solution

1

Applying the cosecant identity: csc⁡(θ)=1sin⁡(θ)\displaystyle\csc\left(\theta\right)=\frac{1}{\sin\left(\theta\right)}

2csc⁡(2x)−tan⁡(x)cos⁡(x)\frac{2\csc\left(2x\right)-\tan\left(x\right)}{\cos\left(x\right)}

Final answer to the exercise

2csc⁡(2x)−tan⁡(x)cos⁡(x)\frac{2\csc\left(2x\right)-\tan\left(x\right)}{\cos\left(x\right)}

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2sin(2x) −tan(x)cos(x) 
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