$\left(x-5\right)^2+\left(-x+1\right)^2=2\left(x^2+1\right)$
$\lim_{x\to0}\left(\frac{tan6t}{tsect}\right)$
$\lim_{x\to0}\left(\left(e^x-1\right)\ln\left(x\right)\right)$
$27m^6p^{12}-64x^{15}$
$\left(3.6\right)\left(3.6\right)$
$26-15c+c^2$
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