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Exercise

$\frac{\frac{x^3+3x^2y+3xy^2+y^3+x+y-1}{2}}{y}$

Step-by-step Solution

1

Divide fractions $\frac{\frac{x^3+3x^2y+3xy^2+y^3+x+y-1}{2}}{y}$ with Keep, Change, Flip: $\frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}$

$\frac{x^3+3x^2y+3xy^2+y^3+x+y-1}{2y}$

Final answer to the exercise

$\frac{x^3+3x^2y+3xy^2+y^3+x+y-1}{2y}$

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