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Exercise

$\frac{\left(\left(-1\right)^k\right)}{2k+1}2\cdot3^{\left(2k+1\right)}$

Step-by-step Solution

1

Multiplying the fraction by $2\cdot 3^{\left(2k+1\right)}$

$\frac{2{\left(-1\right)}^k\cdot 3^{\left(2k+1\right)}}{2k+1}$

Final answer to the exercise

$\frac{2{\left(-1\right)}^k\cdot 3^{\left(2k+1\right)}}{2k+1}$

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