$\log\left(x\right)=3$
$2log\left(x\right)-log\left(x+6\right)=0$
$\log_3\left(x+4\right)+\log_3\left(x-4\right)=2$
$\log\left(4X^2\right)=128$
$\log_x\left(64\right)=3$
$\log_2\left(x-2\right)+\log_2\left(x+1\right)=2$
$2\cdot log\left(x\right)-1\cdot log\left(x+6\right)=0$
Are those equations in which the unknown variable appears within a logarithm.
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