Exercise
$\frac{\left(3x^2+2x-3\right)}{\left(x+4\right)}$
Step-by-step Solution
1
Divide $3x^2+2x-3$ by $x+4$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}+4;}{\phantom{;}3x\phantom{;}-10\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}+4\overline{\smash{)}\phantom{;}3x^{2}+2x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}+4;}\underline{-3x^{2}-12x\phantom{;}\phantom{-;x^n}}\\\phantom{-3x^{2}-12x\phantom{;};}-10x\phantom{;}-3\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}+4-;x^n;}\underline{\phantom{;}10x\phantom{;}+40\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}10x\phantom{;}+40\phantom{;}\phantom{;}-;x^n;}\phantom{;}37\phantom{;}\phantom{;}\\\end{array}$
$3x-10+\frac{37}{x+4}$
Final answer to the exercise
$3x-10+\frac{37}{x+4}$