Learn how to solve synthetic division of polynomials problems step by step online. Simplify the expression (m^3+2m^24m+8)/(m+2). We can factor the polynomial m^3+2m^2+4m+8 using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals 8. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial m^3+2m^2+4m+8 will then be. Trying all possible roots, we found that -2 is a root of the polynomial. When we evaluate it in the polynomial, it gives us 0 as a result.

Simplify the expression (m^3+2m^24m+8)/(m+2)