$$\lim_{x\to1}\left(\frac{\left(ln\:x\right)^2}{x-1}\right)$$

$$\sqrt[3]{32b^2}+5\sqrt[6]{16b^4}-7\sqrt[9]{64b^6}$$

$$y=\frac{x}{2}+\frac{2}{x}$$

$$x=3,\:y=-1,\:z=\:-2$$

$$24x^2-86x+72=0$$

$$x\:=\:\frac{\left(e^{4y}\right)}{z^5}$$