$2x-5<3x+4$
$x-3x^2+x+1+x^3-x^2+5x-2$
$y^2-16y=0$
$\left(8r+h\right)\left(-4j+\:6u\right)$
$\frac{\left(\sin\left(x\right)+\cos\left(x\right)^2\right)}{\sin\left(x\right)}=\csc\left(x\right)+2\cos\left(x\right)$
$x-2+x^2+x-6$
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