$\lim_{x\to-2.99}\frac{\tan\left(x+3\right)}{x+3}$
$-1+12+-3$
$3a\left(x-3y\right)+2b\left(x-3y\right)$
$\left(\frac{x^2+x\cdot\sin\left(x\right)}{\cos\left(x\right)-1}\right)$
$24x^8y^3-16x^6y^7z^3$
$cos^3x\:sin^7x=\left(sin^7x-sin^9x\right)cosx$
$42=7y$
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