$2x^2+x^3-8x^2-x+6$
$2x-3=\sqrt{x+6}$
$\frac{x^{-7}}{x^2}$
$4-\left|7+\left(-3\right)+\left(-2\right)\right|$
$16^{-2}\cdot4^3$
$-9x^4y^2\cdot\:\:16y^3$
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