$\int\left(\frac{5x+1}{6x^2+7x-3}\right)dx$
$1x^2-2x+18$
$10\int\left(sec\:\cdot\:tan\:\right)$
$10\:-\:\left(-7-5\right)$
$\int tan9xsec^29xdx$
$-214.3320-117.0400-194.3817-154.2055-605.3844$
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