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Exercise

$\frac{1}{cos^2x}-2+cos^2x$

Step-by-step Solution

1

Since $\cos$ is the reciprocal of $\sec$, $\frac{1}{\cos\left(x\right)^2}$ is equivalent to $\sec\left(x\right)^2$

$\sec\left(x\right)^2-2+\cos\left(x\right)^2$

Final answer to the exercise

$\sec\left(x\right)^2-2+\cos\left(x\right)^2$

Try other ways to solve this exercise

  • Choose an option
  • Find the derivative
  • Integrate using basic integrals
  • Verify if true (using algebra)
  • Verify if true (using arithmetic)
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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Similar Questions Solved

$\left(\sin\left(x\right)+\cos\left(x\right)\right)^2$

$1+cot^2x$

$tan\left(x\right)csc\left(x\right)$

$\tan\left(x\right)\csc\left(x\right)$

$\frac{2+\tan^2\left(x\right)}{\sec^2\left(x\right)}-1$

$csc^2x-1$

Main Topic: Simplify Trigonometric Expressions

Simplification of trigonometric expressions consists of rewriting an expression with trigonometric functions in a simpler form. To perform this task, we usually use the most common trigonometric identities, and some algebra.

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