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Exercise

$\frac{1}{csc\left(x\right)^2a}$

Step-by-step Solution

1

Applying the trigonometric identity: $\csc\left(\theta \right)^2 = 1+\cot\left(\theta \right)^2$

$\frac{1}{a\left(1+\cot\left(x\right)^2\right)}$
Why does csc(x)^2 = 1+cot(x)^2 ?
2

Multiply the single term $a$ by each term of the polynomial $\left(1+\cot\left(x\right)^2\right)$

$\frac{1}{a+a\cot\left(x\right)^2}$

Final answer to the exercise

$\frac{1}{a+a\cot\left(x\right)^2}$

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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