$\int_e^{\infty}\left(\frac{1}{x\left(ln\left(3x\right)\right)^2}\right)dx$

$\tan\left(x\right)+\tan\left(y\right)=3$

$4x-9+-5x+2$

$\frac{dy}{dx}=\frac{5}{\tan\left(x\right)}+3\left(4-5x\right)^3+6xe^{2-x^2}$

$\int\:\:x^2\left(x^3+1\right)dx$

$\left(3x^{n\:}a^5+x^na^3\right)^2$

$1,2x^2-0,3x+1$