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Exercise

$\frac{100k^4-9}{10k^2+3}$

Step-by-step Solution

1

Factor the difference of squares $100k^4-9$ as the product of two conjugated binomials

$\frac{\left(10k^{2}+3\right)\left(10k^{2}-3\right)}{10k^2+3}$
2

Simplify the fraction $\frac{\left(10k^{2}+3\right)\left(10k^{2}-3\right)}{10k^2+3}$ by $10k^{2}+3$

$10k^{2}-3$

Final answer to the exercise

$10k^{2}-3$

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Main Topic: Factor by Difference of Squares

The difference of two squares is a squared number subtracted from another squared number. Every difference of squares may be factored according to the identity a^2-b^2=(a+b)(a-b) in elementary algebra.

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