limx→∞(ln(1+2x3)4+ln x)\lim_{x\to\infty}\left(\frac{ln\left(1+2x^3\right)}{4+ln\:x}\right)x→∞lim(4+lnxln(1+2x3))
x4−9x2+16x^4-9x^2+16x4−9x2+16
limx→0(e2xe2x−1)\lim_{x\to0}\left(\frac{e^{2x}}{e^{2x-1}}\right)x→0lim(e2x−1e2x)
−0,23+1-0,23+1−0,23+1
−17−1+18+6+4+4-17-1+18+6+4+4−17−1+18+6+4+4
−35x2+73x−18-35x^2+73x-18−35x2+73x−18
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