$\sqrt{x^2+6x+8+1}$
$100-16x^2$
$\int_{-1}^2\left(\frac{3+x}{x-4}\right)dx$
$\left(-256\right)+\left(-149\right)+\left(-318\right)$
$\left(3x+8\right)x\left(3x-8\right)$
$\ln\left(x+5\right)-\ln\left(x+1\right)=1$
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