$5x+10\ge\:-3$
$tan^2\left(3t\right)sec^2\left(3t\right)$
$3^25^8$
$-6\cdot\left(4-10\right)+2\cdot\left(-12\right)$
$15\:+\left|20\:-5\:\left(3-5\right)\right|$
$7\frac{5}{7}$
$2+10q+5-3$
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