$\cos^2x\sec^2x+\tan^2x=\sec^2x$
$\frac{\left(x-5\right)\left(x+7\right)}{12x^6}$
$64x^2+56x+400$
$9-\left(\left(-5\right)-\left(+7\right)\right)$
$0.08\cdot0.08$
$\frac{-2x+1}{3x+2}\le\:1$
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