\frac{2}{3}a^2+\frac{1}{2} ab - 2ab^2- \frac{3}{4}ab + \frac{1}{3}a^2 - \frac{3}{5}b^2

 Exercise

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Math interpretation of the question

$\frac{2}{3a^2}+\frac{1}{2ab}-2ab^2+\frac{-3}{4ab}+\frac{1}{3a^2}+\frac{-3}{5b^2}$

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Combining like terms $\frac{2}{3a^2}$ and $\frac{1}{3a^2}$

$\frac{3}{3}\frac{1}{1a^2}+\frac{1}{2ab}-2ab^2+\frac{-3}{4ab}+\frac{-3}{5b^2}$

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Divide $3$ by $3$

$\frac{1}{1a^2}+\frac{1}{2ab}-2ab^2+\frac{-3}{4ab}+\frac{-3}{5b^2}$

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Any expression multiplied by $1$ is equal to itself

$\frac{1}{a^2}+\frac{1}{2ab}-2ab^2+\frac{-3}{4ab}+\frac{-3}{5b^2}$

$\frac{1}{a^2}+\frac{1}{2ab}-2ab^2+\frac{-3}{4ab}+\frac{-3}{5b^2}$

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