$z^2=\left(x^2\right)+\left(y^2\right)z$
$3x-4y+z=12$
$0x^2-2x^3$
$\left(6+\left(x^2+5\right)^4\right)^3$
$\sqrt{1200}$
$8y-3x-y+x$
$x^2-4x=5$
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