$6\left(-8\right)+4$
$100=d+70m^2+4d-3m^2-y^2+25m^2$
$\lim_{x\to\infty}\left(x\:sen\left(\frac{1}{2}\right)\right)$
$\int\frac{1}{sqrt\left(4+x^2\right)}dx$
$\ln\:\frac{1+xy}{1-xy}-2x$
$\frac{d}{dx}\left(11x^8\:+\:9x^4\:-\:16x\:+\:13\right)$
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