$\frac{d}{dx}\left(\frac{x^6\left(x+1\right)^2}{\left(x-3\right)^5}\right)$
$5-\infty^2-29-\infty+20$
$dy\:-\left(y-1\right)^2dx=0$
$6x^3-6x^2+15x-15$
$x\cdot1-2\cdot7$
$x+3y+2z=2$
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