2x2−5x3−6x+4\frac{2x^2-5}{x^3-6x+4}x3−6x+42x2−5
∫sen (2x+1) dx\int sen\:\left(2x+1\right)\:dx∫sen(2x+1)dx
x6(1+4x)2\frac{x^6}{\left(1+4x\right)^2}(1+4x)2x6
y+13yy+\frac{1}{3}yy+31y
2x5+5x3−12x2+10x−52x^5+5x^3-12x^2+10x-52x5+5x3−12x2+10x−5
x5+2x3−x−8x2+5\frac{x^5+2x^3-x-8}{x^2+5}x2+5x5+2x3−x−8
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