Learn how to solve problems step by step online. Simplify the expression (2x^3+6x^2-x+-3)/(x^3+3x^2x+3). We can factor the polynomial x^3+3x^2+x+3 using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals 3. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial x^3+3x^2+x+3 will then be. Trying all possible roots, we found that -3 is a root of the polynomial. When we evaluate it in the polynomial, it gives us 0 as a result.

Simplify the expression (2x^3+6x^2-x+-3)/(x^3+3x^2x+3)