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Exercise

$\frac{2x^2y^2}{4y^{-1}}$

Step-by-step Solution

1

Simplify the fraction $\frac{2x^2y^2}{4y^{-1}}$ by $y$

$\frac{2x^2y^{\left(2- -1\right)}}{4}$
2

Multiply $-1$ times $-1$

$\frac{2x^2y^{\left(2+1\right)}}{4}$
3

Add the values $2$ and $1$

$\frac{2x^2y^{3}}{4}$
4

Take $\frac{2}{4}$ out of the fraction

$\frac{1}{2}x^2y^{3}$

Final answer to the exercise

$\frac{1}{2}x^2y^{3}$

Try other ways to solve this exercise

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  • Solve by quadratic formula (general formula)
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  • Find the derivative
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  • Find the roots
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Main Topic: Factorization

In mathematics, factorization or factoring is the decomposition of an object (for example, a number, a polynomial, or a matrix) into a product of other objects, or factors, which when multiplied together give the original.

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