$\lim_{x\to2}\left(1228\right)$
$cos\left(5x\right)=0$
$\lim_{x\to0}\left(1+7x\right)^{\frac{3}{x}}$
$5=\frac{g}{8}$
$\lim_{x\to5}\left(\frac{x^2-\cos\left(25\right)}{x-5}\right)$
$32x^{2}-54x^{2}+12$
$x^4-2=0$
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