$f\left(x\right)=12x^2+16x$
$\int16ln8xdx$
$\int_{-\infty}^0\left(x^2e^x\right)dx$
$2a-\sqrt{3b}$
$\left(\left(-5x+9\right)^2\right)$
$12x-4\le12x-6$
$\frac{4}{\left(x-1\right)\left(x+1\right)}$
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