$\frac{\left(6x^2-8x+12\right)}{\left(13x^3-5x^2-9x-27\right)}$

$x^2+10x+25=8$

$\int_0^{\infty}\left(0.0001\right)dx$

$3x+14=4x-6$

$\frac{1}{\sec x+\tan x}+\frac{1}{\sec x-\tan x}$

$\frac{x^4+3x^2+4-2}{x-2}$

$8\cos\left(x\right)^2\:+\:10\cos\left(x\right)=13\:-\:5\sin\left(x\right)^2$