(1−3z2)2\left(1-3z^2\right)^2(1−3z2)2
dydx+14y=x\frac{dy}{dx}+\frac{1}{4}y=xdxdy+41y=x
limx→−1((x+1)(x−3)(x+1)(x+2))\lim_{x\to-1}\left(\frac{\left(x+1\right)\left(x-3\right)}{\left(x+1\right)\left(x+2\right)}\right)x→−1lim((x+1)(x+2)(x+1)(x−3))
y=ln(x⋅cos(x))+5−xy=ln\left(x\cdot cos\left(x\right)\right)+5^{-x}y=ln(x⋅cos(x))+5−x
cos xtan x=32\frac{cos\:x}{tan\:x}=\frac{3}{2}tanxcosx=23
((x3−x)+(x2−3))((x3−x)−(x2−3))\left(\left(x^3-x\right)+\left(x^2-3\right)\right)\left(\left(x^3-x\right)-\left(x^2-3\right)\right)((x3−x)+(x2−3))((x3−x)−(x2−3))
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