$-x^2+4x+1$
$-\left(+4-10-2\right)+\left(-4-5+7\right)+15$
$-\:20\:+\:1\:+\:15\:+\:\:-\:50\:+\:9\:$
$\int\left(\frac{x-4}{\left(x^2+2x+2\right)\left(x-1\right)}\right)dx$
$x^6-x^8$
$\frac{5x-3}{6}+\frac{x-5}{18}<\frac{x+1}{3}$
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