∫5x+6(x−1)(x+4)dx\int\frac{5x+6}{\left(x-1\right)\left(x+4\right)}dx∫(x−1)(x+4)5x+6dx
x2>2−x2x^2>2-x^2x2>2−x2
26⋅2626\cdot2626⋅26
(−2xy2)⋅4xy2\left(-2xy^2\right)\cdot4xy^2(−2xy2)⋅4xy2
4(k+9)4\left(k+9\right)4(k+9)
(60a+10b−9c+d−4)−(a+100b−6c+8d−9)\left(60a+10b-9c+d-4\right)-\left(a+100b-6c+8d-9\right)(60a+10b−9c+d−4)−(a+100b−6c+8d−9)
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