Final answer to the problem
$\frac{\left(8a^{3}+b^{3}\right)\left(64a^{6}-8a^{3}b^{3}+b^{6}\right)}{2a+b}$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
Can't find a method? Tell us so we can add it.
1
Factor the sum or difference of cubes using the formula: $a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2)$
$\frac{\left(\sqrt[3]{512a^9}+\sqrt[3]{b^9}\right)\left(\sqrt[3]{\left(512a^9\right)^{2}}-\sqrt[3]{512a^9}\sqrt[3]{b^9}+\sqrt[3]{\left(b^9\right)^{2}}\right)}{2a+b}$
Learn how to solve problems step by step online.
$\frac{\left(\sqrt[3]{512a^9}+\sqrt[3]{b^9}\right)\left(\sqrt[3]{\left(512a^9\right)^{2}}-\sqrt[3]{512a^9}\sqrt[3]{b^9}+\sqrt[3]{\left(b^9\right)^{2}}\right)}{2a+b}$
Learn how to solve problems step by step online. Simplify the expression (512a^9+b^9)/(2a+b). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). The power of a product is equal to the product of it's factors raised to the same power. Calculate the power \sqrt[3]{512}. The power of a product is equal to the product of it's factors raised to the same power.
Final answer to the problem
$\frac{\left(8a^{3}+b^{3}\right)\left(64a^{6}-8a^{3}b^{3}+b^{6}\right)}{2a+b}$
