Exercise
$\frac{5x^3+7x^2+x-1}{x^2+1}$
Step-by-step Solution
1
Divide $5x^3+7x^2+x-1$ by $x^2+1$
$\begin{array}{l}\phantom{\phantom{;}x^{2}+1;}{\phantom{;}5x\phantom{;}+7\phantom{;}\phantom{;}}\\\phantom{;}x^{2}+1\overline{\smash{)}\phantom{;}5x^{3}+7x^{2}+x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}+1;}\underline{-5x^{3}\phantom{-;x^n}-5x\phantom{;}\phantom{-;x^n}}\\\phantom{-5x^{3}-5x\phantom{;};}\phantom{;}7x^{2}-4x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}+1-;x^n;}\underline{-7x^{2}\phantom{-;x^n}-7\phantom{;}\phantom{;}}\\\phantom{;-7x^{2}-7\phantom{;}\phantom{;}-;x^n;}-4x\phantom{;}-8\phantom{;}\phantom{;}\\\end{array}$
$5x+7+\frac{-4x-8}{x^2+1}$
Final answer to the exercise
$5x+7+\frac{-4x-8}{x^2+1}$